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1+7x-x^2=0
We add all the numbers together, and all the variables
-1x^2+7x+1=0
a = -1; b = 7; c = +1;
Δ = b2-4ac
Δ = 72-4·(-1)·1
Δ = 53
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{53}}{2*-1}=\frac{-7-\sqrt{53}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{53}}{2*-1}=\frac{-7+\sqrt{53}}{-2} $
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